I have an @api.one method and need the id of the current record. Like the other magic field as create_date aso., I can get this fields into a view but I didn'd find a solution to get them into @api.one method. If I try "print self.create_date" the result is false.
This question is pretty old but for anyone who wandered looking for an answer,
Try: "self._origin.id"
Create an account today to enjoy exclusive features and engage with our awesome community!
साइन अप करें| Related Posts | Replies | डेटा देखने का तरीका | ऐक्टिविटी | |
|---|---|---|---|---|
|
1
जून 19
|
7272 | ||
|
0
सित॰ 19
|
98 | ||
|
1
जुल॰ 17
|
6252 | ||
|
4
अग॰ 16
|
11123 | ||
|
1
मई 16
|
7324 |
1. Use the live chat to ask your questions.
2. The operator answers within a few minutes.
self.id didn't work?
No self.id gets the following result: "openerp.models.NewId object at 0x7f36a85bd250" But actually I don't work in new record.
Simply use the ids value defined in method defination def method_name(self, cr, uid, ids, ,context=None)
Sorry Shivam, I don't understand your comment. I'm not so used in the old API. Do I have to create a method to get the ID?